Question

A 2.0-kg bowling ball is held at arm’s length, a distance of 0.70 m from the shoulder joint. What torque does the ball exert about the shoulder, if the arm is horizontal?

**with explanation please, answer is 14 N m

Answer 1

Given

mass of ball m = 2 kg, perpendicular distance r = 0.70 m from the shoulder

   the force acting at adistance 0.7 m about the shoulder is

   Torque T = r*F sin theta

      = r*F*sin theta

       = r *mg*sin theta
       = r*mg*sin 90

       = 0.7*2*9.8*1
       = 13.72 N

so the torque does the ball exert about the shoulder is 14 N