What is the energy released in this nuclear reaction 95247Am → 96247Cm + -10e? (The atomic mass of 247Am is 247.072091 u and that of 247Cm is 247.070354 u)
PLEASE, DO NOT ROUND NUMBERS. Thanks!
From change in mass we can calculate its energy equivalent using Einstein's equation, E = mc2.
1 u = 1.6605 ×× 10-27 kg
mass of electron = 0.00055 amu
Now Mass on Left side (Reactants) = (247.072091) = 247.072091 u
Mass on right side (Products) = (247.070354) + 10*(0.00055) = 247.075854 amu
Change in mass = 23471.8486 amu - 23718.759484 amu = -0.00376299999 atomic mass units
Energy Released = ( -0.00376299999 amu)(1.6606 x 10-27 kg/amu)(2.9979 x 108 m/s)2 =-5.6160832\10^(-13) J
Negative sign hence exothermic
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