Question

CM, 1D, extended mass: A rod of length L = 1.0 m has constant mass per...

CM, 1D, extended mass: A rod of length L = 1.0 m has constant mass per unit length λ given by LM=λ, where M is the total mass of the rod. For this problem, the parameter x is the distance from the left end of the rod. a)By observation alone, what do you think is the center of mass, cmx, of the rod (in symbols, then numbers)? This answer should be obvious. The point of what follows is to get this same result using integration, and to help you understand the integration process. b)Sketch a diagram. At an arbitrary position x, imagine an infinitesimal piece with length dx. i)Make a list of the properties of this piece (position, mass, length, mass per unit length), and assign symbols/equations to each. ii)What is the mass dm of this piece? (in terms of given parameters) c)Integrate to find the center of mass, cmx (symbols first, then numbers). Does your answer agree with what you already know?

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A uniform rod of mass M = 20 kg and length L = 5m is bent...
A uniform rod of mass M = 20 kg and length L = 5m is bent into a semicircle. What is the gravitational force exerted by the rod on a point mass m = 0.1 kg located at the center of the circular arc? Please show all work and step by step, thank you!
The uniform thin rod in the figure below has mass M = 2.00 kg and length...
The uniform thin rod in the figure below has mass M = 2.00 kg and length L = 2.87 m and is free to rotate on a frictionless pin. At the instant the rod is released from rest in the horizontal position, find the magnitude of the rod's angular acceleration, the tangential acceleration of the rod's center of mass, and the tangential acceleration of the rod's free end. HINT An illustration shows the horizontal initial position and vertical final position...
A uniform rod of mass M = 20 kg and length L = 5m is bent...
A uniform rod of mass M = 20 kg and length L = 5m is bent into a semicircle. What is the gravitational force exerted by the rod on a point mass m = 0.1 kg located at the center of the circular arc? If the answers are going to be written please do it legible, thanks
Given a thin, straight rod of length L lying on the x axis, extending from the...
Given a thin, straight rod of length L lying on the x axis, extending from the originx=0 to x=L. The rod carries total charge +Q uniformly distributed over its length. We want to find the net electric field E du to this rod at point P (b,0) on the x axis, with b>L (that means P lies outside (“to the right of”) the rod. Again, let’s do it step-by-step— (a) Sketch the setup. (b) At an arbitrary location x somewhere...
A rod with length L and mass M hangs vertically on a frictionless, horizontal axel passing...
A rod with length L and mass M hangs vertically on a frictionless, horizontal axel passing through its center. A ball of mass m traveling horizontally at speed v0 hits and sticks to the very bottom tip of the rod. To what maximum angle, measured from vertical, does the rod, with the attached ball, rotate? Answer in terms m, M, v0, L, and g.
A rod of length l=0.8m and mass M= 3.7kg joins two particles with masses m1 =4.5kg...
A rod of length l=0.8m and mass M= 3.7kg joins two particles with masses m1 =4.5kg and m2 = 2.8kg, at its ends. The combination rotates in the xy-plane about a pivot through the center of the rod with the linear speed of the masses of v= 3.5 m/s. (Moment of inertia of a uniform rod rotating about its center of mass I= 1 12 M l2 a) Calculate the total moment of inertia of the system b) What is...
A rod of length l=1.1m and mass M= 5.5kg joins two particles with masses m1 =4.8kg...
A rod of length l=1.1m and mass M= 5.5kg joins two particles with masses m1 =4.8kg and m2 = 2.8kg, at its ends. The combination rotates in the xy-plane about a pivot through the center of the rod with the linear speed of the masses of v= 3.5 m/s. (Moment of inertia of a uniform rod rotating about its center of mass I= 1 12 M l2 ) angularmomentum a) Calculate the total moment of inertia of the system I...
A rod of length l=2.2m and mass M= 9.7kg joins two particles with masses m1 =12.9kg...
A rod of length l=2.2m and mass M= 9.7kg joins two particles with masses m1 =12.9kg and m2 = 5.0kg, at its ends. The combination rotates in the xy-plane about a pivot through the center of the rod with the linear speed of the masses of v= 12.9 m/s. (Moment of inertia of a uniform rod rotating about its center of mass I= 1 12 M l2 ) a) Calculate the total moment of inertia of the system I =...
A uniform rod of length L and mass M is free to swing about an axis...
A uniform rod of length L and mass M is free to swing about an axis that is perpendicular to the rod. The axis is a distance x from the rod's center of mass. a) Find the period of oscillations for small angles as a function of L and x with appropriate constants. b) make a sketch of the period as a function of x. If you use a spread sheet you may assume that L=1.0 m, then your graph...
A uniform rod of mass mr = 173 g and length L = 1... A uniform...
A uniform rod of mass mr = 173 g and length L = 1... A uniform rod of mass mr = 173 g and length L = 100.0 cm is attached to the wall with a pin as shown. Cords are attached to the rod at the r1 = 10.0 cm and r2 = 90.0 cm mark, passed over pulleys, and masses of m1 = 246 g and m2 = 127 g are attached. Your TA asks you to determine...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT