Question

A 100 microfarad capacitor is charged to 24 volts DC. How much charge is placed on each plate and how much energy is stored in the capacitor? If that capacitor is discharged in 100 microseconds, how much power did it deliver during that time?

Answer 1

a) We know that

Q=CV

here C=100F , V=24 Volts

So

Q=100F×24Volts

Q=2400C

Q=2.4 mC

One plate has Q=2.4mC and other one has Q'=-2.4mC

b) the energy stored in the Capacitor

U=CV^2/2

U=100F(24volts)^2/2

U=28,800J

U=28.8 mJ Answer

here m=10^(-3)

C) Using work-energy principles

W=∆U. ...1

We know that the power

P=W/t

Using equation 1

P=∆U/t

P=(U2-U1)/t

here U2=28800J , U1=0 ,t=100s

P=(28800J-0)/100s

P=288 Watts .