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A 15.0 kg object is moving at 8.50 m/s. A constant force then acts on the...

A 15.0 kg object is moving at 8.50 m/s. A constant force then acts on the object for 2.25 seconds, bringing its final velocity to 3.75 m/s in the opposite direction. a. Calculate the impulse acting on the object b. What is the magnitude and direction of the force? c. What is the momentum of the object before and after the force acts?

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Answer #1

A) Net impulse acting on obj ct is equal to the change in momentum so,

So plug in value we get,

B) So magnitude of constant force is given by,

And direction of of force is opposite of motion because final velocity is less than initial velocity.

C) So before force acts mometum is

And final momentum is

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