How much energy is required to change a 55-g ice cube from ice at 0°C to steam at 140°C? J
step;1
Given that
mass m=0.055 kg
step;2
now we find the energy required
the heat energy ice to water at )C
Q1=mL=0.055*3.34*10^5 =18370 J
the heat energy from water at 0C to 100 C
Q2=0.055*4200[100-0]=23100 J
the heat energy required from 100 C to steam at 100 C
Q3=0.055*2.26*10^5=12430 J
the heat energy required from 100 to 140 C
Q4=0.055*2058[140-100]=4527.6 J
the net amount of heat energy required
Qnet=Q1+Q2+Q3+Q4
=[4527.6+12430+23100+18370]
=56319.54 J
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