A 2.14 μF capacitor and a 5.62 μF capacitor are connected in series across an 18.0 V battery. What voltage would be required to charge a parallel combination of the same two capacitors to the same total energy?
therefore , V2 = (5.02 x 10-4) / (7.76 x 10-6)
= 64. 69
thus , V = 64. 69
= 8.04 V (answer)
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