Question

1. An object of mass M oscillates on a spring with maximum amplitude A. If the amplitude is doubled, how will it change the period?

The period is increased by a factor of 2

The period is increased by a factor of 4

The period is decreased by a factor of 2

The period is decreased by a factor of 4

The period stays the same

2. In the “Resonance” lab, you used a “piano” to generate a frequency of 261.63 Hz to explore the different resonance lengths. With it you found the first resonance close to 33 cm. Where would you expect to find the next resonance?

66 cm

99 cm

49.5 cm

132 cm

3. Wave Interference is one term that can be used to describe what happens when two or more waves combine (either constructively or destructively). What term did we use in these labs to describe this general combining of two or more waves?

Superposition

Standing Wave

Interaction

Wave Mechanics

Harmonic Waves

4. In the “Resonance” lab, you used a “piano” to generate a frequency of 261.63 Hz to explore the different resonance lengths. With it you found the first resonance close to 33 cm. This resonance was found in an atmosphere of air. What would happen if you replaced the air with sulfur hexafluoride? Note that the speed of sound in sulfur hexafluoride is 135 m/s. The speed of sound in air is 343 m/s.

The first resonance would be found at a length shorter than 33 cm because the wavelength decreases.

The first resonance would be found at a length larger than 33 cm because the wavelength decreases.

The first resonance would be found at a length shorter than 33 cm because the wavelength increases.

The first resonance would be found at a length larger than 33 cm because the wavelength increases.

Answer #1

1) T=2π √(K/M)

It doesn't depends on amplitude

2) resonance frequency

L(1) = v/4f°. L(2) = 3v/4f°

33 = v/4f°

L(2) = 3* (v/4f°) = 3× 33 = 99 cm

3)

When **two or more waves** combine superposition
occurs

4)

L(n) = (n*V)/(4f)

Resonance length velocity

If velocity increase the resonance length also increase.

In this case the velocity decrease so first resonance also decrease because of decrease in λ (wave length )

As V = f* λ

So velocity is also praposional to wavelength.

In the “Resonance” lab, you used a “piano” to generate a
frequency of 261.63 Hz to explore the different resonance lengths.
With it you found the first resonance close to 33 cm. Where would
you expect to find the next resonance?
A.66cm
B. 99 cm
C. 49.5 cm
D. 132 cm
please show work
in the “Resonance” lab, you used a “piano” to generate a
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With it you found the...

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