Question

A solar collector device (assume an efficiency of 50%) is located at the outer limits of the atmosphere at 45 degrees, The collector faces south with its flat receiving surface placed in a vertical position. Calculate the total energy absorbed by the collector per unit of collector area during the full day of June 15.

Answer 1

The energy density of light is given by

U= (cn₀/ 2)(E²)

Her c=speed of light

        n=refracive index of the medium

         ₀= permitivity of free space

        E=complex amplitude of the electric field

The complex amplitude is given by   E= e^i(wt-kx)

            U=(Cn₀/2) e^i(wt-kx)

            U=( Cn₀/2) e^i(45-Kx)

               In order to find the numerical value of energy we have to deal the quantum probability of energy .

         ( U)=   (Cn₀/2) integeral    eⁱ⁽45-kx)             limit 0 t0 2

                  Solving this intergeral you can find the numerical value.