On a hot day, the temperature of an 60,000 L swimming pool increases by 1ºC . What is the net heat transfer (in MJ) during this heating? Ignore any complications, such as loss of water by evaporation. The specific heat of the swimming pool is 4186 J/kgºC.
ANS : From, S = Q / m x
Q = m s
Given : m = 60000 x 1000 = 6 x 107 g = 6 x 104 Kg
= 10C , S = 4186 J/kgºC.
Therefore , Q = 6x 104 x 4186 x 1
Q = 25116 x 10 4 J
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