How much work is required to compress 80 grams of Argon gas (A presubscript 20 presuperscript 40 r ) to half its original volume if you hold it's temperature at 20 degress C?
A. 3,375 joules
B. 12,450 joules
C. 4723 joules
D. 1,112 joules
work done while temperature is kept constant = nRT ln(V2/V1)
now mole, n= 80/40 = 2
temperature, T = 20+273 =293 K
R = 8.31 J/KgK
i.e. W= 2*8.31*293* ln(2) = 3375 J
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