No, the particle can still accelerate.
Let us take a simple example , a free falling object of mass M starting from rest , from a certain height h under the action of gravity.
At , height h , K.E = 0
P.E = Mgh
Total mechanical energy E = K.E + P.E
= Mgh
When the object falls a distance d , and attains a speed V ,
K.E = 0.5 MV2
= 0.5 M ( 2gd)
= Mgd ( since , V2 = 0 +2gd )
P.E = Mg( h-d )
Total mechanical energy at the position
E = K.E + P.E
= Mgd + Mg(h-d )
= Mgh
SO, total energy is conserved but have an acceleration of g .
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