Question

A 285-Ω resistor is in series with a 35.5 *μ*F capacitor
and a 27.0-V voltage source with the circuit switch open and the
capacitor uncharged.

(a) What is the time constant of this *RC* circuit?

10.1175 ms

(b) Calculate the maximum charge the capacitor can
accumulate.

.000972 C

(c) Calculate the charge on the capacitor 5.25 ms after the switch
is closed.

.0005785083113C

Please check my answers.

Thanks!

Answer #1

given

R = 285 ohm

C = 35.5 micro F

V_battery = 27.0 V

a) Time constant of the circuit, T = R*C

= 285*35.5*10^-6

= 0.0101175 s (or) 10.1175 ms <<<<<<<------------Answer

b) maximum charge on the capacitor, Q_max = C*V_battery

= 35.5*10^-6*27

= 0.0009585 C <<<<<<<------------Answer

c) at time t = 5.25 ms

Q = Q_max*(1 - e^(-t/T))

= 0.0009585*(1 - e^(-5.25/10.1175))

= 0.0003880 C <<<<<<<-------------Answer

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