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A mirror is showing upright image of a person standing 1.2 m from it. Image is...

A mirror is showing upright image of a person standing 1.2 m from it. Image is 2.8 times taller than a person. What is the radius of curvature of this mirror? Give the answer in meters.

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Answer #1

Given the object distance u is 1.2m and the magnification of the image is M = 2.8. By sifn convention u = -1.2m. If f is the focal length of the mirror, then

So the magnitude of focal length of the mirror is 1.87m. Since its value is negative, the mirror is concave.

If R is the radius of curvature of the mirror, then

So the magnitude of the radius of curvature of the mirror is 3.74m.

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