Question

Under constant pressure, the temperature of 1.70 mol of an ideal monatomic gas is raised 15.5...

Under constant pressure, the temperature of 1.70 mol of an ideal monatomic gas is raised 15.5 K. (a) What is the work W done by the gas? J (b) What is the energy transferred as heat Q? J (c) What is the change ΔEint in the internal energy of the gas? J (d) What is the change ΔK in the average kinetic energy per atom? J

Homework Answers

Answer #1

a)At constant pressure, work done by gas
W = nR ΔT
n is number of moles of gas, R (gas constant) = 8.3
so W = 1.7 x 8.3 x 15.5 = 218.7 J

b) At constant pressure Q = n Cp ΔT
Cp is molar specific heat at constant pressure and = (f+2)R/f
f is degree of freedom. for monoatomic gas f = 3
So Q = 1.7 x 8.3 x (5/3) 15.5 = 364.5 J

c) Q = ΔE + W
hence ΔE = Q - W = 145.8 J

d) Kinetic energy per atom = f Kb T/2
Kb = R/Na , Na is avogadro number ( 6.2 x 1023 )

so change in KE per atom ΔK = f Kb ΔT /2
   = 3 x 8.3 15.5 / 2 x 6.2 x 1023  = 3.1x10-22 J

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