Question

A football is kicked with a speed of 20 m/s at an angle of 37 degrees to the ground.

● (a) What is the maximum height that it reaches?

● (b) How far has it travelled horizontally when it reaches its maximum height?

● (c) What is the total time the football spends in the air?

Answer #1

**at the maximum height final speed = 0**

**along vertical**

**vy^2 - voy^2 = 2*ay*dy**

**0 - (20*sin37)^2 = -2*9.8*h**

**height h = 7.4 m <<<======ANSWER**

**-------------**

**part(b)**

**from equation of motion**

**vy = voy + ay*t**

**0 = (20*sin37) - (9.8*t)**

**t = 1.23 s**

**x = vx*t = vo*cos3*t**

**x = 20*cos37*1.23**

**x = 19.65 m <<<<==========ANSWER**

**==================**

**part(c)**

**after falling on grond**

**y = 0**

**y = voy*T + (1/2)*ay*T^2**

**0 = (20*sin37*T) - ((1/2)*9.8*T^2)**

**T = 2.46 s <<<==========ANSWER**

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