Question

A particle of mass m and charge q enters a region of magnetic field, in a...

A particle of mass m and charge q enters a region of magnetic field, in a direction that is prependiuclar to the field boundary. The particle then exits the region in the opposite direction to the one it entered the field, 7.7 ms later. The distance between the point of entry and exit is 14.5 mm. If the particle is 4 times the mass of a proton, and carries 20 times the charge of a proton, what is the field strength?

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Answer #1

Solution :

Given :

t = 7.7 ms = 7.7 x 10-3 s

d = 14.5 mm = 14.5 x 10-3 m

m = 4 mp = 4 (1.67 x 10-27 kg) = 6.68 x 10-27 kg

q = 20 e = 20 x 1.6 x 10-19 C = 32 x 10-19 C

.

When a charged particle enters into the magnetic field perpendicular to it. Then the charge will follow a spherical path.

And, the period of the spherical motion is given by :

Here, we have : T = 2 t = 2(7.7 x 10-3 s) = 15.4 x 10-3 s

Thus, from the above equation :

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