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Now the charges Q1= 1.73·10-6 C and Q2= -2.65·10-6 C are fixed at their positions, distance...

Now the charges Q1= 1.73·10-6 C and Q2= -2.65·10-6 C are fixed at their positions, distance 0.279 m apart, and the charge Q3= 3.18·10-6 C is moved along the straight line. For what position of Q3 relative to Q1 is the net force on Q3 due to Q1 and Q2 zero? Use the plus sign for Q3 to the right of Q1In the above problem, Q1= 1.73·10-6 C, Q2= -2.65·10-6 C, and Q3= 3.18·10-6 C. Calculate the total force on Q2. Give with the plus sign for a force directed to the right.

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