Question

A 6 kg mass and a 20 kg mass on a horizontal frictionless surface are connected by a massless string A. They are pulled horizontally across the surface by a second string B that is attached to the 20 kg mass. Both masses have a constant acceleration of 8 m/s2.

What is the magnitude of the net force on the 6 kg mass?

What is the magnitude of the force of string A on the 20 kg mass?

What is the magnitude of the net force on the 20 kg mass?

What is the magnitude of the force of string B on the 20 kg mass?

Answer 1

for 6 kg mass

Fnet = 6*a

magnitude of the net force on the 6 kg mass ,FA = 6*8 = 48 N <<=========ANSWER

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for 20 kg mass

from newtons third law force on 6kg bt sting is equal to force exerted by srting A on 20 kg

TA= Fnet on 6 kg = 48 N   <<=========ANSWER

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for 20 kg

from newtons second law

Fnet = m*a

Fnet on 20 kg = 20*a = 160 N <<=========ANSWER

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Fnet = 160

TB - TA = 160

TB - 48 = 160

Tb = 208 N <<<=========ANSWER