Question

The drawing shows three different resistors in the circuit shown below. The battery has a voltage of V = 26 V, and the resistors have resistances of R1 = 50.0 Ω, R2 = 25.0 Ω and R3 = 10.0 Ω. Determine the current through and the voltage across each resistor.

Answer 1

A) if there is a series circuit so the current is the same through all three resistors and is the total current through circuit which we can find from Ohm’s law.

R=R1+R2+R3=50+25+10=85 ohms

V=26 volts

i1=i2=i3=V/R=26/85=0.306 amps

V1=i1*R1=15.3 volts

V2=i2*R2=7.65 volts

V3=i3*R3=3.06 volts

B)if circuit is a parallel circuit so the Voltage across each resistor is the same as the power source so

V1=V2=V3=V=26 volts

i1=V/R1=26/50=0.52 A

i2=26/25=1.04A

i3=26/10=2.6 A