Question

A bike air valve is 0.3m from centr of a uniformly spinning wheel, moving tangentialy along the wheel perimetr at 6.2m/s.

A. Can you figure out how fast the bike is moving, ifso answer in m/s. what else might you need to answr?

B. What is the tangential acceleration of the air valve? Answer in m/s^2

C. What is the centripetal acceleration of the air valve? Answer in m/s^2 ?

D. What is the angular velocity of the wheel? Answer in rev/s.

Answer 1

Here,

A) No, we can't find the speed of the bike. For that we need the radius of the tyre.

B) tangential acceleration of air valve = dv/dt

as the angular speed is constant

tangential acceleration of air valve = 0 m/s^2

C)

centripetal acceleration = v^2/r

centripetal acceleration = 6.2^2/0.30

centripetal acceleration = 128.13 m/s^2

D)

angular velocity of the wheel = v/r

angular velocity of the wheel = 6.2/0.30

angular velocity of the wheel = 20.7 rad/s

angular velocity of the wheel = 3.3 rev/s