(8c7p44) The loaded cab of an elevator has a mass of 4000 kg and moves 207 m up the shaft in 31 s at constant speed. At what average rate does the force from the cable do work on the cab?
mass m = 4000 kg
elevator is moving with constant sped. so net force is T -m g = 0
T = m g = 4000 x 9.8 = 39200 N
S = 207 m
time t = 31 sec
rate of work or power P = F X S / t = 39200 x 207 / 31 = 261754 .8 watts
= 2.6 x 10^5 watts
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