Question

9. For a converging lens, when is the image upright? When is the image inverted?Can you...

9. For a converging lens, when is the image upright? When is the image inverted?Can you use arbitrary rays to find the position of the image?

Science   Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

  • Among all the positions shown above, the image will be upright (erect) only when the object is placed between the principal focus and optic center.
  • For all the position except when the object is placed between the principal focus and optic center, the image is inverted.
  • Arbitrary rays cannot be used to find the position of the images. All rays dawn must be according to the set of rules for drawing the the rays falling through lens.
0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
True or False a) A converging lens can produce a virtual, upright, enlarged image. b) A...
True or False a) A converging lens can produce a virtual, upright, enlarged image. b) A diverging lens always produces a virtual, upright, reduced image. c) For a converging lens an object has to be placed between the focal point and the lens in order to form a virtual image. d) A converging lens can never produce a virtual, upright, reduced image. A converging lens cannot produce a real, inverted reduced image. e) A diverging lens can produce a real,...
Consider how a converging lens produces a virtual image opposed to a real image. a. Would...
Consider how a converging lens produces a virtual image opposed to a real image. a. Would the virtual image be upright or inverted? Is it larger or smaller than the object itself? b. Can you observe this image on a screen placed in front of the lens? Explain c. Suppose you move the object closer to the lens. Is the image upright or inverted? Is it larger or smaller than the object itself? d. If the object is closer to...
When using a converging lens, how does the object’s location affect whether an image is (a)...
When using a converging lens, how does the object’s location affect whether an image is (a) enlarged (bigger than the object) or reduced (smaller than the object) (b) upright or inverted?
When using a converging lens, how does the object’s location affect whether an image is (a)...
When using a converging lens, how does the object’s location affect whether an image is (a) enlarged (bigger than the object) or reduced (smaller than the object) (b) upright or inverted?
A converging lens with a focal length of 12 cm forms a real image of 8...
A converging lens with a focal length of 12 cm forms a real image of 8 mm tall, 17 cm to the right of the lens. (a) Determine the position and size of the object (b) Is the image upright or inverted? (c) Are the object and image on the same side or opposite sides of the object? (d) Draw a ray-diagram for this situation
A diverging lens with a focal length of -19.7 cm and a converging lens with a...
A diverging lens with a focal length of -19.7 cm and a converging lens with a focal length of 11.0 cm have a common central axis. Their separation is 39.5 cm. An object of height 1.1 cm is 26.4 cm in front of the diverging lens, on the common central axis. Find the location of the final image produced by the combination of the two lenses. Where is the image located as measured from the converging lens? What is the...
An object 2.0 cm high is placed 40.0 cm to the left of a converging lens...
An object 2.0 cm high is placed 40.0 cm to the left of a converging lens having a focal length of 30.0 cm. A diverging lens with a focal length of- 20.0 cm is placed 110.0 cm to the right of the converging lens. Determine a) the position of the final image, b) the magnification of the final image, c) Is the image upright or inverted? ANS q= 20 cm M=-6 (inverted)
A 6-cm-high candle is placed in front of a converging lens with a focal length of...
A 6-cm-high candle is placed in front of a converging lens with a focal length of magnitude 30 cm. If the image distance is +50 cm, then find the image height of the candle and whether it is upright or inverted. answer: 4cm, inverted i need help understnading which eqution to use to complete this problem. Also could you explain how ot determine if an image is real, inverted, or upright? thank you will rate asap
Consider a converging lens whose focal length is 5.47 cm. An object is placed on the...
Consider a converging lens whose focal length is 5.47 cm. An object is placed on the axis of the lens at a distance of 11.7 cm from the lens. 1. How far is the object's image from the lens? In centimeters. 2. If it can be determined, is the image real or virtual? virtual real cannot be determined 3. If it can be determined, is the image upright or inverted with respect to the object? inverted upright cannot be determined
A converging lens with a focal length of 12.0cmforms a virtual image 8.00mm tall, 17.0cm to...
A converging lens with a focal length of 12.0cmforms a virtual image 8.00mm tall, 17.0cm to the right of the lens. Part A Determine the position of the object. s =   cm   Part B Determine the size of the object. |y| =   cm   Part C Is the image erect or inverted? Is the image erect or inverted? The image is erect. The image is inverted. Part D Are the object and image on the same side or opposite sides of...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT