Question

Four people with a combined mass of 300 kg are riding in a 1100 kg car. When they drive down a washboard road with bumps spaced 6.9 mm apart, they notice that the car bounces up and down with a maximum amplitude when the car is traveling at 6.1 m/s . The driver stops the car and everyone exits the vehicle.

Part A) How much does the car rise up on its springs?

Answer 1

Solution:

Using the simple harmonic motion of the car,

Frequency,

f = v/x = 6.1/6.9*10^-3

= 884.06 Hz

Angular frequency,

= 2f = 2*884.06

= 5554.7 rad/s

A) The car raising up is the amplitude of the SHM,

A = v_max/

= 6.1/5554.7

= 1.098*10^-3 m

= 1.1 mm,

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