Question

An object i 5 cm in front of diverging lens (focal length 10 cm). 20 cm behind diverging lens is converging lens (focal length 20 cm). where is the image? is it real or virtual?

Answer #1

**Given**

**focal length of diverging lens is f1 = -10
cm**

**object distance is s1 = 5 cm**

**the relation between object distance , image distance
and focal length is **

**1/s +1/s' = 1/f**

**1/s1' = 1/f1 -1/s1**

**1/s1' = -1/10 -1/5**

**s1' = -3.33 cm**

**that is the image is formed infront of the
lens **

**it will act as the object to the converging
lens **

**the object distance s2 = 20+3.33 = 23.33 cm**

**focal length of the converging lens is f2 = 20
cm**

**the image distance is**

**1/s2' = 1/f2 -1/s2**

**1/s2' = 1/20 -1/23.33**

**s2' = 140.120 cm = 1.40120 m**

**the image is real image and inverted also**

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