Question

Concept Simulation 25.2 illustrates the concepts pertinent to this problem. A 2.50-cm-high object is situated 18.3 cm in front of a concave mirror that has a radius of curvature of 9.22 cm. Calculate (a) the location and (b) the height of the image.

Answer 1

h = height of object = 2.50,
u = object distance = - 18.3 cm
f = R/2 = - 9.22/2 = - 4.61 cm
--------------------mirror formula
1/v + 1/u = 1/f
v = image distance = f *u/[u-f]
v = [- 18.3] *[- 4.61] /[- 18.3 + 4.61]
v = - 6.162cm
image formed will be at (6.1cm) from concave mirror to the left of itself
-------------------------
magnification = m = h'/h = image size/object size = - v/u
h'/2.50 = - [- 6.162]/[- 18.3]
h' = - 0.841 cm
-ve sign shows image is inverted