Question

A horizontal compass is held on the surface of the Earth directly over a buried powerline with a current of 200 A heading due south. The compass is 5 m above the powerline. In what direction does the compass needle point at this location andwhat is the magnitude of the total magnetic field at this point? Assume the horizontal component of the Earth’s field at this point is 0.45 x 10‐4 T and is directed due north.

Answer #1

A horizontal compass is placed 0.26 m due south from a straight
vertical wire carrying a 42 A current downward. Assume the
horizontal component of the Earth's field at this point is 0.45E-4
T. In what direction does the compass needle point at this
location? Give your answer as a decimal fraction of degrees west of
north.

Lab Scenario:
You don't have a current meter in your underequipped lab.
So you make one out of a compass.
The wire you want to measure the current in is aligned with the
North South line.
You place your compass directly under the wire at a distance of
10cm from the wire.
With no current flowing, the compass needle points due
north.
When you turn on the current, the compass needle points 5
degrees west of north.
You now have...

At a certain location, Earth has a magnetic field of 0.60 ✕ 10−4
T, pointing 75° below the horizontal in a north-south plane. A 11.1
m long straight wire carries a 12 A current.
(a) If the current is directed horizontally toward the east,
what are the magnitude and direction of the magnetic force on the
wire?
magnitude
N
direction
---Select---
(b) What are the magnitude and direction of the force if the
current is directed vertically upward?
magnitude
N...

At a point on the Earth’s surface the magnetic field has a
horizontal component due north of 1.8 ́ 10-5 T and a vertical
component downwards of 5.5 ́ 10-5 T.
(i) Draw a diagram.
(ii) Calculate the force on a 1.5 m length of wire carrying a
current of 13 A when the wire is held vertically with the current
flowing downwards.
(iii) Calculate the force when the wire is horizontal with the
current flowing west to east.

A circular coil of wires (N = 10 turns, R = 3.5 cm) is oriented
so that the axis of the coil runs east to west. A compass pointing
north sits a distance of d = 12 cm from the center of the coil and
lies on the axis of the coil. The horizontal component of the
Earth’s magnetic field at this location has a magnitude of 2.5×10−5
T. When a current is turned on the compass needle now points...

Horizontal electric power lines supported by vertical poles can
carry large currents. Assume that Earth’s magnetic field runs
parallel to the surface of the ground from south to north with a
magnitude of 0.50×10−4 T and that the supporting poles are 38 m
apart.
Find the magnitude and direction of the force that Earth’s
magnetic field exerts on a 38 m segment of wire carrying 95 A if
the current runs toward the northeast making an angle of 30∘∘ north...

Measuring Magnetic Fields] The horizontal component of the
Earth’s magnetic field is 2 x 10-5 Tesla. Suppose you
bring a bar magnet such that it is 3 cm from a magnetic compass.
The bar magnet makes the compass deflect 15.6 degrees. What is the
strength of the magnetic field due to the bar magnet at that
location? Suppose this bar magnet is a magnetic dipole.
What is the value of the magnetic dipole moment? Remember that

Two hikers are reading a compass under an overhead transmission
line that is 5.30 m above the ground and carries a current of 790 A
in a horizontal direction from north to south.
Find the direction of the magnetic field at a point on the
ground directly under the conductor.
I already know the answer so I just need a full explanation why,
I did the right-hand rule but its wrong so how?

A wire with a mass of 1.21 g/cm is placed on a horizontal
surface with a coefficient of friction of 0.200. The wire carries a
current of 1.41 A eastward and moves horizontally to the north.
What are the magnitude and the direction of the smallest
magnetic field that enables the wire to move in this fashion?
magnitude _____ T
Direction _________

A proton is circling the Earth above the magnetic equator, where
Earth’s magnetic field is directed horizontally north and has a
magnitude of 4.00 × 10–8 T. If the proton is moving at a speed of
2.7 × 107 m/s, how far above the surface of the Earth is the
proton? Earth’s radius is 6.38 × 106 m, a proton’s mass is 1.67 ×
10–27 kg, and its charge is 1.6 × 10–19 C.
a. 7.05E+6 m
b. 1.34E+7 m...

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