Unless otherwise stated, all objects are located near the
Earth's surface, where g = 9.8 m/s2.
A hockey puck with a weight of 0.10 lb is sliding freely across a
section of very smooth (frictionless) horizontal ice.
Calculate the upward force on the puck in both situations. (lb)
Solution: Given Information:
A hockey puck with a weight of 0.10 lb is sliding freely across a section of very smooth (frictionless) horizontal ice.
To find:the upward force on the puck in both situations
Using formula
F = ma
F = (0.0453592)(9.8) = 0.4445 N =0.09992 lb
then we use newton's 3rd law to solve.
F1 + F2 = 0.
Hence, F1 = -F2. So the upward force (including direction) =
-0.4445 N=-0.09992 lb (assuming down is positive and up is
negative)
*I converted lbs to kg*
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