Question

A ray of light impinges from air onto a block of ice (n = 1.309) at a 62.0° angle of incidence. Assuming that this angle remains the same, find the difference ?2, ice ? ?2, water in the angles of refraction when the ice turns to water (n = 1.333). ?2, ice ? ?2, water = _____°

Answer 1

Apply Snell's law.

For ice    sin i / sin r = n_ice = 1.309

    sin 62⁰ / sin ?_2ice = 1.309

    sin ?_2ice = 42.42⁰

For water     sin i / sin?₂ = 1.333

   sin ?₂ = sin 68⁰ / 1.333  

   ?₂ = 44.2 ^{0
Calculate the required angle difference}
   Therefore the difference  ?_2ice - ?₂

= 45.42 - 44.20 = 1.22⁰  

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