A doubly ionized molecule (i.e., a molecule lacking two electrons) moving in a magnetic field experiences a magnetic force of 5.33×10−16 N as it moves at 369 m/s at 68.5∘ to the direction of the field. Find the magnitude of the magnetic field.
We have given that molecule is doubly ionized
So charge q=2e=2×1.6×10-19=3.2×10-19c
Magnetic force is given by F = 5.33×10-16N
velocity is given as v = 369 m/sec
Angle =68.5
We know that magnetic force is given by
F=qvBsin
Now magnetic field B=F/qvsin
Substituting all the required values in above equation.
Therefore B=5.33×10-16/(3.2×10-19×369×sin68.5)
B=4.851T
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