At 17°C, a rod is exactly 20.10 cm long on a steel ruler. Both the rod and the ruler are placed in an oven at 261°C, where the rod now measures 20.21 cm on the same ruler. What is the coefficient of linear expansion for the material of which the rod is made?
Given
rod
initial
T1 = 17 0C, l1 = 20.10 cm = 0.2010 m
final
T2 = 261 0C, l2 = 20.21 cm = 0.2021 m
change in length is Dl = l2-l1 =0.2021 - 0.2010 = 0.0011
m
change in temperature is DT = T2-T1 = 261-17 = 244 0C
now the linear thermal expansion is Dl = l1*alpha(DT)
now the coefficient of linear expansion alpha = Dl/(l1*DT)
alpha = 0.0011/(0.2010*244)
alpha = 2.24288394*10^-5 / 0C
the coefficient of linear expansion for the material of which the rod is made alpha = 2.24288394*10^-5 / 0C
Get Answers For Free
Most questions answered within 1 hours.