What is the change in speed (in m/s) due to the Bernoulli effect as water goes into a 2.72 cm-diameter nozzle from a 8.69 cm-diameter fire hose while carrying a flow of 40.4 L/s?
Given : r2 = 1.36cm =0.0136 m
r1= 4.345cm= 0.0434 m ,
ρ 1000kg/m , g = 9.8m/s^2 , Q = 40.4 L/s
Plugging known information to get :
According to Continuity Equation,
Where:
Q = the volumetric flow rate
A = the cross sectional area of flow
V = the mean velocity
Similarly,
Change in speed, v2 - v1 = 0.945 - 0.296 = 0.649 m/s => Δv= 0.65 m/s.
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