A wire of radius 0.15 mm is made of an unknown metal and carries a current of 8.4 mA. The drift velocity for electrons in the wire is measured to be 36 x 10-6 m/s. What is the carrier density of the metal from which the wire is made?
a. 4.2 x 1030 m-3 |
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b. need more information to do this calculation. |
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c. 4.2 x 1028 m-3 |
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d. 1.3 x 1029 m-3 |
Current through the conductor is
where e is the charge of the electron, n is the carrier density, A is the crossectional area, is the drift velocity.
Given:
I = 8.4 mA= 8.4*10^-3 A
m^2
e= 1.60217662 × 10-19 C
So carrier density
Actual answer is
The closed answer is option c.
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