Question

When a carpenter shuts off his circular saw, the 10.0-inch diameter blade slows from 4210 rpm...

When a carpenter shuts off his circular saw, the 10.0-inch diameter blade slows from 4210 rpm to zero in 3.00 s .

A. What is the angular acceleration of the blade?

α =   rev/s2  

Part B

What is the distance traveled by a point on the rim of the blade during the deceleration?
s =

  ft

Part C

What is the magnitude of the net displacement of a point on the rim of the blade during the deceleration?
d =   in
Science   Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
When a carpenter shuts off his circular saw, the 10.0-inch-diameter blade slows from 4217 rpm to...
When a carpenter shuts off his circular saw, the 10.0-inch-diameter blade slows from 4217 rpm to zero in 1.75 s . What is the angular acceleration of the blade? What is the distance traveled by a point on the rim of the blade during the deceleration? What is the magnitude of the net displacement of a point on the rim of the blade during the deceleration?
When a carpenter shuts off his circular saw, the 10.0-inch-diameter blade slows from 4971 rpm to...
When a carpenter shuts off his circular saw, the 10.0-inch-diameter blade slows from 4971 rpm to zero in 1.75 s . 1.What is the angular acceleration of the blade? 2.What is the distance traveled by a point on the rim of the blade during the deceleration? 3.What is the magnitude of the net displacement of a point on the rim of the blade during the deceleration?
When a carpenter shuts off his circular saw, the 10.0-inch diameter blade slows from 4830 rpm...
When a carpenter shuts off his circular saw, the 10.0-inch diameter blade slows from 4830 rpm to zero in 3.00 s . 1. What is the distance traveled by a point on the rim of the blade during the deceleration? 2. What is the magnitude of the net displacement of a point on the rim of the blade during the deceleration?
When a carpenter shuts off his circular saw, the 10.0-inch-diameter blade slows from 4488 rpm to...
When a carpenter shuts off his circular saw, the 10.0-inch-diameter blade slows from 4488 rpm to zero in 1.25 s . Part A What is the angular acceleration of the blade? (Express your answer to three significant figures.) (answer in rad/s2) Part B What is the distance traveled by a point on the rim of the blade during the deceleration?(Express your answer to three significant figures.) (answer in ft.) Part C What is the magnitude of the net displacement of...
When a carpenter shuts off his circular saw, the 10.0-inch-diameter blade slows from 4987 rpm to...
When a carpenter shuts off his circular saw, the 10.0-inch-diameter blade slows from 4987 rpm to zero in 2.25 s . What is the distance traveled by a point on the rim of the blade during the deceleration? What is the magnitude of the net displacement of a point on the rim of the blade during the deceleration?
When a carpenter shuts off his circular saw, the 10.0-inch-diameter blade slows from 4957 rpm to...
When a carpenter shuts off his circular saw, the 10.0-inch-diameter blade slows from 4957 rpm to zero in 3.25 s . A) What is the angular acceleration of the blade? Express your answer to three significant figures. (units=rad/s^2) B) What is the distance (ft) traveled by a point on the rim of the blade during the deceleration? Express your answer to three significant figures. C) What is the magnitude of the net displacement of a point on the rim of...
When a carpenter shuts off his circular saw, the 10.0 inch diameter blade slows from 4680rpm...
When a carpenter shuts off his circular saw, the 10.0 inch diameter blade slows from 4680rpm to zero in 1.25s. A.) what is the angular acceleration of the blade? B) what is the distance traveled by a point on the tim of the blade during the acceleration? (The answer will be in feet) C.) what is the magnitude of the net displacement of a point on the rim of the blade during deceleration? (Answer will be in inches)
A circular saw blade with radius 0.190 m starts from rest and turns in a vertical...
A circular saw blade with radius 0.190 m starts from rest and turns in a vertical plane with a constant angular acceleration of 2.00 rev/s2. After the blade has turned through 155 rev, a small piece of the blade breaks loose from the top of the blade. After the piece breaks loose, it travels with a velocity that is initially horizontal and equal to the tangential velocity of the rim of the blade. The piece travels a vertical distance of...
A 32 cm -diameter circular saw blade has a mass of 0.84 kg , distributed uniformly...
A 32 cm -diameter circular saw blade has a mass of 0.84 kg , distributed uniformly as in a disk. a) What is its rotational kinetic energy at 2700 rpm ? b) What average power must be applied to bring the blade from rest to 2700 rpm in 3.5 s ?
An electric turntable 0.780 m in diameter is rotating about a fixed axis with an initial...
An electric turntable 0.780 m in diameter is rotating about a fixed axis with an initial angular velocity of 0.300 rev/s . The angular acceleration is 0.894 rev/s2 . Part A Compute the angular velocity after a time of 0.192 s Part B Through how many revolutions has the blade turned in this time interval?    Part C What is the tangential speed of a point on the tip of the blade at time t = 0.192 s ? Part...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT