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The density of ice is 917 kg/m3, and the density of sea water is 1025 kg/m3....

The density of ice is 917 kg/m3, and the density of sea water is 1025 kg/m3. A swimming polar bear climbs onto a piece of floating ice that has a volume of 6.83 m3. What is the weight of the heaviest bear that the ice can support without sinking completely beneath the water?

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Answer #1

Density of ice = 917 kg/m^3
Volume of ice = 6.83 m^3
Mass of ice = Volume x Density = 917 x 6.83 = 6263.11 kg
Weight of ice = 6263.11 x g = 61378.478 N
Density of sea water = 1025 kg/m^3

When the bear is on top, the WHOLE ice will b submerged, meaning the whole volume of the ice is underwater.

Buoyant force = V(d)(g) , where V is the volume of ice, d is the density of the SEA WATER, g is the gravitational acceleration.

Buoyant force = (6.83 )(1025)(9.8) = 68607.35 N

The weight of the bear = Buoyant force - Weight of ice = 7228.872 N

Mass of bear = Weight of bear / 9.8 = 737.64 kg

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