A 4.5 kg box slides down a 4.8-m -high frictionless hill, starting from rest, across a 2.0-m -wide horizontal surface, then hits a horizontal spring with spring constant 520 N/m . The other end of the spring is anchored against a wall. The ground under the spring is frictionless, but the 2.0-m-long horizontal surface is rough. The coefficient of kinetic friction of the box on this surface is 0.24.
Part A
What is the speed of the box just before reaching the rough surface?
Express your answer to two significant figures and include the appropriate units.
Part B
What is the speed of the box just before hitting the spring?
Express your answer to two significant figures and include the appropriate units.
Part C
How far is the spring compressed?
Express your answer to two significant figures and include the appropriate units.
Part D
Including the first crossing, how many complete trips will the box make across the rough surface before coming to rest?
A)PE at the top will be:
PE = m g h = 4.5 x 9.8 x 4.8 = 211.68 J
from energy conservation:
KE(bottom) = PE(top)
1/2 m v^2 = 211.68
v = sqrt (2 x 211.68/4.5) = 9.7 m/s
Hence, v = 9.7 m/s
b)Work done by the froctional force is:
Wf = Ff x d
Wf = (mu m g) d
Wf = 0.24 x 4.5 x 9.8 x 2 = 21.17 J
Ke just before hitting is:
KE = Ke(bottom) - Wf
KE = PE(top) - Wf = 211.68 - 21.17 = 190.51
1/2 m v'^2 = 192.51 J
v' = sqrt (2 x 190.51/4.5) = 9.2 m/s
Hence, v' = 9.2 m/s
C)again from conservation of energy
1/2 m v^2 = 1/2 k x^2
x = v sqrt (m/k)
x = 9.2 sqrt (4.5/520) = 0.86 m
Hence, x = 0.86 m
D)Each time box crosses the frictional surface it looses 21.17 J of energy so number of trips would be:
N = PE(top)/Wf = 211.68/21.17 = 9.99 = 10
Hence, N = 10
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