A normal near point is 25 cm away. Bob is very farsighted with a near point at 100 cm. What is the power (in diopters) of the eyeglasses that Bob needs for reading?
let F be the focal length of required lens .
since bob wants to make the image of object at 25 cm at 100 cm to view it clearly , so we have
object distance =u=25 cm
image distance =v=100cm
Now according to lens formula
1/(focal lenght ) = 1/(image distance ) - 1/(object distance ) = 1/(100) - 1/(25 ) = -3 /100 cm -1 = -3 m-1
and also power=1/(focal lenght )=-3 m-1 = -3 diopters
so the power (in diopters) of the eyeglasses that Bob needs for reading is -3 Diopter
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