Question

Light of 650 nm wavelength illuminates a single slit of width 0.20 mm. (Figure 1) shows the intensity pattern seen on a screen behind the slit. You may want to review (Pages 941 - 943) . Figure1 of 1The graph shows intensity as a function of distance. Distance is measured from 0 to 3 centimeters on the x-axis. No values or units are given for the intensity on the y-axis. A large central peak is positioned at 1.5 centimeters with much smaller secondary and tertiary peaks flanking it. The width of the central peak is 1 centimeter. The secondary peaks are positioned at approximately 0.67 centimeters and 2.3 centimeters. The graph shows intensity as a function of distance. Distance is measured from 0 to 3 centimeters on the x-axis. No values or units are given for the intensity on the y-axis. A large central peak is positioned at 1.5 centimeters with much smaller secondary and tertiary peaks flanking it. The width of the central peak is 1 centimeter. The secondary peaks are positioned at approximately 0.67 centimeters and 2.3 centimeters.

Part A What is the distance to the screen? Express your answer to two significant figures and include the appropriate units.

Answer 1

Since you want to calculate the distance from the slit to the screen, you can use the expression for destructive interference since they give us the width of the maximum center.

if the valous and , thus.

therefore, if the width of the central pick is , then:

it use the approximation