Question

A 41.9-kg block of ice at 0 °C is sliding on a horizontal surface. The initial speed of the ice is 8.83 m/s and the final speed is 3.69 m/s. Assume that the part of the block that melts has a very small mass and that all the heat generated by kinetic friction goes into the block of ice, and determine the mass of ice that melts into water at 0 °C.

Answer 1

Mass m = 41.9 kg

Initial speed u = 8.84 m / s

Final speed v = 3.69 m / s

Heat generated by kinetic frictional force Q = ( 1/ 2) m[ u^ 2- v ^ 2]

                                                                  = 1348.19J

mass of ice melts M = Q / L

where L = latent heat of fusion = 334.88 * 10 ^ 3 J /kg

plug it we get M = 4.515 * 10 ^ -3 kg

                          = 4.515 g