Question

a hemispherical bowl of radius 0.5m is filled with water of density 997 kg/m^3. calculate the force exerted on the bowl.

the answer is 3840 N. but When I calculate it, I get 815 N. What's wrong?

Answer 1

given
R = 0.5 m
rho = 997 kg/m^3
we know, volume of sphere, V = (4/3)*pi*R^3
volume of hemisphere, V = (1/2)*(4/3)*pi*R^3 (

= (1/2)*(4/3)*pi*0.5^3

= 0.2618 m^3

mass of the water, m = density*volume

= 997*0.2618

= 261 kg

weight of the water, W = m*g

= 261*9.8

= 2558 N

The force that acts on the bowl = weight of the water

= 2558 N <<<<<<-------------answer

Note : for the given data 2558 N is the correct answer. Please check the given data once.