Question

A cruise-ship passenger uses a shuffleboard cue to push a shuffleboard disk of mass 0.40 kg...

A cruise-ship passenger uses a shuffleboard cue to push a shuffleboard disk of mass 0.40 kg horizontally along the deck so that the disk leaves the cue with a speed of 8.5 m>s. The disk then slides a distance of 8.0 m before coming to rest.

Find the coefficient of kinetic friction between the disk and the deck.

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Answer #1

Gravitational acceleration = g = 9.81 m/s2

Mass of the shuffleboard disk = m = 0.4 kg

Coefficient of kinetic friction between the disk and the deck =

Friction force on the shuffleboard disk = f

f = mg

Initial speed of the disk = V = 8.5 m/s

Distance traveled by the disk before coming to rest = D = 8 m

The kinetic energy of the disk is lost to the work done against friction.

mV2/2 = fD

mV2/2 = mgD

V2/2 = gD

(8.5)2/2 = (9.81)(8)

= 0.46

Coefficient of kinetic friction between the disk and the deck = 0.46

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