Question

A block is oscillating on a spring scale with a period of 4.60
s. At *t* = 0.00 s the package has zero speed and is at
*x* = 8.30 cm. At what time after *t* = 0.00 s will
the package first be at *x* = 4.15 cm?

Answer #1

Time period of oscillation, T = 4.60 s

Angular speed of te oscillating block, ω = (2 π) / T = (2π / 4.60) rad/s

Let the amplitude of oscillation is A

Then, the position of the block is

x(t) = A sin (ω t + φ) ; where φ is the phase

Now we will the given conditions to find out the position of the spring.

**Condition 1:** At t = 0.00 s, x = 8.30 cm

**Condition 2:** At t = 0.00 s, speed of the block,
v = 0.00 cm/s

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