Question

An object is launched with an initial velocity of 50.0 m/s at a launch angle of 36.9∘ above the horizontal. Determine x-values at each 1 s from t = 0 s to t = 6 s. Determine y-values at each 1 s from t = 0 s to t = 6 s. Determine vx-values at each 1 s from t = 0 s to t = 6 s. Determine vy-values at each 1 s from t = 0 s to t = 6 s. Determine the speed v at each 1 s from t = 0 s to t = 6 s. Plot a graph of the object’s trajectory during the first 6 s of motion.

Answer #1

Initial Horizontal velocity = 50*COS(Radians(36.9)) = 40m/sec

Horizontal velocity remains constant as there is no acceleration or
deceleration in horizontal direction.

Vertical Direction:

At t = 0sec, v = 30-((9.81)*0) = 30m/sec => Speed =
50m/sec

At t = 1sec, v = 30-((9.81)*1) = 20.19m/sec => Speed =
44.80665241m/sec

At t = 2sec, v = 30-((9.81)*2) = 10.38m/sec => Speed =
41.32486419m/sec

At t = 3sec, v = 30-((9.81)*3) = 0.57m/sec => Speed =
40.00406104m/sec

At t = 4sec, v = 30-((9.81)*4) = -9.24m/sec => Speed =
41.05335065m/sec

At t = 5sec, v = 30-((9.81)*5) = -19.05m/sec => Speed =
44.30465551m/sec

At t = 6sec, v = 30-((9.81)*6) = -28.86m/sec => Speed =
49.32443208m/sec

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