A wire carries a current with a magnitude I = 0.25 A. What is the magnitude of the magnetic field induced by the current at a distance of 0.13 m from the wire?
A. 7.7×10−7 T
B. 3.8×10−7 T
C. 2.6×106 T
D. 1.9×10−7 T
From Biot-savart law
Magnetic field due to a current carrying wire at distance of a is equal to ° I / 2a
Where ° = permittivity of free space =4×10^(-7)
I = current carrying =0.25 A
a=0.13 m
Magnetic field = 4××10^(-7)×0.25/(2××0.13)
= 3.8×10^(-7) T
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