Question

What mass of steam at 100 degrees C must be added to 2.15kg of ice at 0 degrees C to yield liquid water at 30 degrees C?

Answer #1

= 2.15*333550 = 717132.5 J.

Heat required raising its temperature of water from 0° C to 30 °
C

= 2.15*4186*30 =269997

Total heat required = 987129.5J

--------------------------------------...

Heat to be removed from steam at 100° C to convert into water at
100° C

= 2260000* M.

Heat to be removed to cool water at 100° to water at 16 ° C

= M*4186* [100 -30] =293020 M

Total heat to be removed = 2525555 M J

--------------------------------------...

2525555 M = 987129.5

M = 0.138kg of steam

What mass of steam at 125 degrees C must be added to 2.50 kg of
ice at -28.0 degrees C to yield liquid water at 90.0 degrees F?
Show all your work - equations, units, conversions, etc.

What mass of steam at 100∘C must be added to 1.10 kg of ice at
0∘C to yield liquid water at 19 ∘C? The heat of fusion for water is
333 kJ/kg , the specific heat is 4186 J/kg⋅C∘ , the heat of
vaporization is 2260 kJ/kg .

Part A
What mass of steam at 100∘C must be added to 1.90 kg of ice at
0∘C to yield liquid water at 18 ∘C? The heat of fusion for water is
333 kJ/kg , the specific heat is 4186 J/kg⋅C∘ , the heat of
vaporization is 2260 kJ/kg .
Express your answer to two significant figures and include the
appropriate units.
m =

What mass of steam at 100∘C must be added to 1.00 kg of ice at
0∘C to yield liquid water at 18 ∘C? The heat of fusion for water is
333 kJ/kg , the specific heat is 4186 J/kg⋅C∘J/kg⋅C∘ , the heat of
vaporization is 2260 kJ//kg .
Express your answer to two significant figures and include the
appropriate units
m=

What mass of steam at 160 degree C must be mixed with 150g of ice
at 0 degree C, in a thermally insulated container, to produce
liquid water at 60 degrees C? Specific heat (heat capacity) of
water is 1 cal/gC, of steam 0.48 cal/gC and of ice 0.5 cal/gC.
Latent heat of melting for ice is 80 cal/g. Latent heat of
vaporization for steam is 540 cal/g.

What mass of ice at -10.0∘∘C must be added to 52.0 g of steam at
120∘∘C to end up with water at 40.0∘∘C? (Express your answer to
three significant figures.)

What mass of steam at 100°C must be mixed with 216 g of ice at
its melting point, in a thermally insulated container, to produce
liquid water at 65.0°C? The specific heat of water is 4186 J/kg·K.
The latent heat of fusion is 333 kJ/kg, and the latent heat of
vaporization is 2256 kJ/kg.

What mass of steam at 100°C must be mixed with 162 g of ice at
its melting point, in a thermally insulated container, to produce
liquid water at 71.0°C? The specific heat of water is 4186 J/kg·K.
The latent heat of fusion is 333 kJ/kg, and the latent heat of
vaporization is 2256 kJ/kg.

What mass of steam at 100°C must be mixed with 260 g of ice at
its melting point, in a thermally insulated container, to produce
liquid water at 73.0°C? The specific heat of water is 4186 J/kg·K.
The latent heat of fusion is 333 kJ/kg, and the latent heat of
vaporization is 2256 kJ/kg

What mass of steam at 100°C must be mixed with 301 g of ice at
its melting point, in a thermally insulated container, to produce
liquid water at 16.0°C? The specific heat of water is 4186 J/kg·K.
The latent heat of fusion is 333 kJ/kg, and the latent heat of
vaporization is 2256 kJ/kg.

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