Question

Naturally occurring 40K is listed as responsible for 16 mrem/y of background radiation. Calculate the mass...

Naturally occurring 40K is listed as responsible for 16 mrem/y of background radiation. Calculate the mass of 40K that must be inside the 55-kg body of a woman to produce this dose. Each 40K decay emits a 1.32-MeV ββ, and 50% of the energy is absorbed inside the body.

Science   Advanced-Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Most of the internal radiation of the human body is due to a single isotope, the...
Most of the internal radiation of the human body is due to a single isotope, the beta emitter 40K, with half life of 1.28×109 years. The body contains about 0.35% potassium by mass; of this potassium, about 0.012% is 40K. • What is the total activity, in Bq, of a 70 kg human? • Each 40K decay produces a 1.3 MeV beta particle. If 40% of the energy of these decays is absorbed by the body, what dose, and what...
Problem 5:   The annual radiation dose from 14C in our bodies is 0.01 mSv/y. Each 14C...
Problem 5:   The annual radiation dose from 14C in our bodies is 0.01 mSv/y. Each 14C decay emits a β– averaging 0.0750 MeV. Taking the fraction of 14C to be 1.3 × 10–12 of normal 12C, and assuming the body is 13% carbon, estimate the fraction of the decay energy absorbed. (The rest escapes, exposing those close to you.) You can assume the relative biological effectiveness is 1, and recall the half-life of Carbon-14 is 5730 yrs.
a 60 Co y-ray source used in radiation therapy has an activity of 5*10^9 Bq. the...
a 60 Co y-ray source used in radiation therapy has an activity of 5*10^9 Bq. the half life if 69 Co id 5.36 years. a.) what is the mass if the 60 Co in the source? b) this source is used to deliver radiation to a .2 kg tumor. it is placed so that 50% of the radiation from the source is absorbed by the tumor. each decay delivers an average of 1.2MeV of energy. the treatment lasts for 10...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT