Question

Two 15 Ω and three 25 Ω light bulbs and a 24 V battery are connected in a series circuit. What is the current the passes through each bulb?

Answer #1

There are two types of bulb connected in series , two bulb with 15 ohm resistance and three bulb with 25 ohm resistance.

In series combination the total or equivalent resistance is given as

Therefore total resistance =

Current in the circuit =

= 24/105 = 0.23 amp

Since in series combination same current passes through each element, hence current through each bulb = 0.23 amp

A 24-V battery is connected to two resistors, 56.0 Ω and 82.0 Ω,
which are joined together in series. (a) What is the current and
power for each resistor? (b) What is the current and power for each
resistor if you join them in parallel instead?

1. Two light bulbs of resistance 10.0-Ω and 20.0-Ω are connected
to a voltage source of 3 V. (a) How would you connect them to get
minimum current? Draw the circuit diagram.
Calculate the total current in the circuit.
(b) How would you connect them to get maximum current? Draw the
circuit diagram.
Calculate the total current in the circuit.
Calculate the current through each resistor

4, 8, and 12 Ω resistors are connected series with 24 V
battery. Find current through each resistor and potential
difference across individual resistors.

A battery with an emf of 12.0 V shows a terminal voltage of 11.2
V when operating a circuit with four light bulbs, two in parallel
connected in series with the other two also in a parallel
arrangement, each rated at 6 W (at 12.0 V).
(a) Draw a diagram of the arrangement.
(b) What is the total external resistance of this circuit?
(c) What is the current in each bulb?
(d) What is the internal resistance of the battery?

Three light bulbs each of resistance 25 ohms are connected ina
parallel circuit and connects to a 9.0volt battery to complete the
circuit. What is the voltage across each resistor!

Three resistors of 12 Ω , 12 Ω , and 6.0 Ω are connected in
parallel. A 12-V battery is connected to the combination. What is
the current through the 6.0 Ω resistor?
Three capacitors of 12 μF, 12 μF, and 6.0 μF are connected in
series. A 12-V battery is connected to the combination. What is the
charge on the 6.0 μF capacitor?

1a) Two light bulbs are hooked up in a series to a 9 V battery.
Why is the voltage drop across a single light bulb not 9 V?
1b) Suppose someone hands you three resistors having three
different resistances. How would you hook them up in order to make
their equivalent resistance as small as possible, and thus the
largest current? (Briefly explain why your arrangement produces the
smallest equivalent resistance.)

1/
If three 10 Watt light bulbs are connected in series to a 60V power
supply, what is the current throught each bulb?
2/ If a 4th 10 Watt bulb is added in series, would each bulb
burn brighter , dimmer, or remain in the same as before the bulb
was added, and why?[Hint: consider what would happen to the
current.]

A circuit consists of two resistors, 1.80 Ω and 9.79 Ω,
connected in series. The combination of resistors is connected to a
12.0 V battery. Calculate a) the equivalent resistance of the
circuit, b) the current in the circuit, and c) the total power
usage of the circuit.

A light bulb is wired in series with a 132-Ω resistor, and they
are connected across a 120-V source. The power delivered to the
light bulb is 22.3 W. What are the two possible resistances of the
light bulb?
lower value
_________ Ω
higher value
_________ Ω

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