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Two 15 Ω and three 25 Ω light bulbs and a 24 V battery are connected...

Two 15 Ω and three 25 Ω light bulbs and a 24 V battery are connected in a series circuit. What is the current the passes through each bulb?

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Answer #1

There are two types of bulb connected in series , two bulb with 15 ohm resistance and three bulb with 25 ohm resistance.

In series combination the total or equivalent resistance is given as

Therefore total resistance =

Current in the circuit =

= 24/105 = 0.23 amp

Since in series combination same current passes through each element, hence current through each bulb = 0.23 amp

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