A coil of wire has a resistance of 34.2 Ω at 28.0 °C and 38.6 Ω at 62.0 °C. What is the temperature coefficient of resistivity [(oC)-1]?
__________________________________________
Rt = R t0 (1 + T)
= ((Rt / R t0 ) - 1) * (1/T)
T = 62 - 28 = 34
= ((38.6/34.2) -1) * (1/34)
= 0.003783969 K-1 = 3.784 * 10-3 (oC)-1
__________________________________________
Please rate
if any mistake in this answer please comment i will clarify your
doubt . thank you
Get Answers For Free
Most questions answered within 1 hours.