Question

A coil of wire has a resistance of 34.2 Ω at 28.0 °C and 38.6 Ω at 62.0 °C. What is the temperature coefficient of resistivity [(oC)-1]?

Answer 1

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R_t = R _t0 (1 + T)

= ((R_t / R _t0 ) - 1) * (1/T)

T = 62 - 28 = 34

= ((38.6/34.2) -1) * (1/34)

= 0.003783969 K^-1 = 3.784 * 10^-3 (^oC)^-1

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