Question

A 36.0 kg child runs with a speed of 2.80 m/s tangential to the rim of...

A 36.0 kg child runs with a speed of 2.80 m/s tangential to the rim of a stationary merry-go-round. The merry-go-round has a moment of inertia of 512 kg⋅m2 and a radius of 2.48 m. When the child jumps onto the merry-go-round, the entire system begins to rotate. What initial speed does the child have if the angular speed of the system after the collision is 0.500 rad/s?

Science   Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

Considering the axis of rotation of the merry-go-round, the Angular Momentum of the merry-go-round and the child will be conserved if the rotation of the merry-go-round is assumed frictionless.The situation befor the child jumps on the merry-go-round is shown:

Let the velocity of the child be v as shown, mass of child be m, moment of inertia be I and angular velocity of the entire system be w.

Using Conservation of Angular momentum, as the child is on the merry-go-round its tangential speed with respect to the ground is w*r

The child has an initial speed of 4.1074 m/s.

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A 40.0 kg child runs with a speed of 2.90 m/s tangential to the rim of...
A 40.0 kg child runs with a speed of 2.90 m/s tangential to the rim of a stationary merry-go-round(Figure 1). The merry-go-round has a moment of inertia of 580 kg?m2and a radius of 2.51 m . When the child jumps onto the merry-go-round, the entire system begins to rotate. A) Calculate the initial kinetic energy of the system. (J) B)Calculate the final kinetic energy of the system. (J)
A child of mass m=45kg runs at a speed v=3m/s tangent to the rim of a...
A child of mass m=45kg runs at a speed v=3m/s tangent to the rim of a merry-go-round when it is at rest, and then jumps onto it. The merry-go-round has a mass M=140kg, a radius R=1.1m, and can be thought of as uniform disk. Neglecting friction in the bearings, find the angular velocity of the merry-go-round once the child jumped on.
A playground merry-go-round has a moment of inertia of 600 kg m2. When the merry-go-round is...
A playground merry-go-round has a moment of inertia of 600 kg m2. When the merry-go-round is at rest, a 20 kg boy runs at 5.9 m/s along a line tangential to the rim and jumps on, landing on the rim a distance of 3.0 m from the rotation axis of the merry-go-round. The angular velocity of the merry-go-round is then: A.1.2 rad/s B.0.38 rad/s C.0.45 rad/s D.0.56 rad/s E.0.72 rad/s
A playground merry-go-round has a radius of 3.0 m and a rotational inertia of 600 kg-m^2....
A playground merry-go-round has a radius of 3.0 m and a rotational inertia of 600 kg-m^2. When the merry-go-round is at rest, a 20-kg child runs at 5.0 m/s along a line tangent to the rim and jumps on. The angular velocity of the merry-go-round is then: .45 rad/s 1.2 rad/s .38 rad/s .56 rad/s .71 rad/s
A 40 kg child moving at 3 m/s runs in a straight line and jumps on...
A 40 kg child moving at 3 m/s runs in a straight line and jumps on a 2 metre radius merry go round. The merry go round has inertia 55 kg m2. Find the heat energy created by this collision answer: 46.05J
A disk-shaped merry-go-round of radius 2.63 m and mass 155 kg rotates freely with an angular...
A disk-shaped merry-go-round of radius 2.63 m and mass 155 kg rotates freely with an angular speed of 0.558 rev/s. A 59.4 kg person running tangential to the rim of the merry-go-round at 3.58 m/s jumps onto its rim and holds on. Before jumping on the merry-go-round, the person was moving in the same direction as the merry-go-round's rim. (a) Does the kinetic energy of the system increase, decrease, or stay the same when the person jumps on the merry-go-round?...
IP A disk-shaped merry-go-round of radius 2.84 m and mass 155 kg rotates freely with an...
IP A disk-shaped merry-go-round of radius 2.84 m and mass 155 kg rotates freely with an angular speed of 0.62 rev/s . A 61.1 kg person running tangential to the rim of the merry-go-round at 3.17 m/s jumps onto its rim and holds on. Before jumping on the merry-go-round, the person was moving in the same direction as the merry-go-round's rim. Part B Calculate the initial kinetic energy for this system. Part C Calculate the final kinetic energy for this...
A disk-shaped merry-go-round of radius 2.93 m and mass 185 kg rotates freely with an angular...
A disk-shaped merry-go-round of radius 2.93 m and mass 185 kg rotates freely with an angular speed of 0.621 rev/s . A 60.4 kg person running tangential to the rim of the merry-go-round at 3.51 m/s jumps onto its rim and holds on. Before jumping on the merry-go-round, the person was moving in the same direction as the merry-go-round's rim. What is the final angular speed of the merry-go-round?
A 20-kg child running at 2.0 m/s jumps onto a playground merry-go-round that has inertia 180...
A 20-kg child running at 2.0 m/s jumps onto a playground merry-go-round that has inertia 180 kg and radius 1.6 m. She is moving tangent to the platform when she jumps, and she lands right on the edge. Ignore any friction in the axle about which the platform rotates. What is the rotational speed of the merry-go-round and the child if the merry-go-round started from rest? Express your answer with the appropriate units.
A disk-shaped merry-go-round of radius 2.13 m and mass 185 kg rotates freely with an angular...
A disk-shaped merry-go-round of radius 2.13 m and mass 185 kg rotates freely with an angular speed of 0.631 rev/s . A 58.4 kg person running tangential to the rim of the merry-go-round at 3.11 m/s jumps onto its rim and holds on. Before jumping on the merry-go-round, the person was moving in the same direction as the merry-go-round's rim. Part A What is the final angular speed of the merry-go-round?
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT