Question

In the diagram below, the two charges *q*_{1} =
+*q* and *q*_{2} = −2*q* are fixed in
place. The distance between them is *d* = 3.87 m. Find the
distance *x* of the point A on the horizontal line where the
net electric potential due to the two charges is zero.

_____ m

Answer #1

....

(12.) In nuclear fission, a nucleus splits
roughly in half. (a) What is the potential 3.00 ✕
10-14 m from a fragment that has 46 protons in it? 2.21e+06 V
[My Answer 2.21e+6 V] (b) What is
the potential energy in MeV of a similarly charged fragment at this
distance? [My Answer 102 MeV]
(13) In one of the classic nuclear physics
experiments at the beginning of the 20th century, an alpha particle
was accelerated toward a gold nucleus, and...

A charge q1 = 1.92 µC is at a distance d = 1.63 m from a second
charge q2 = −5.97 µC. a) Find the electric potential at a point A
between the two charges that is d/3 from q1. Note that the location
A in the diagram above is not to scale. b) Find a point between the
two charges on the horizontal line where the electric potential is
zero. (Enter your answer as measured from q1.)

Two particles having charges q1 = 0.400 nC and
q2 = 6.00 nC are separated by a distance of 1.60 m .
At what point along the line connecting the two charges is the
total electric field due to the two charges equal to zero?

1) You have two charges; Q1 and Q2, and
you move Q1 such that the potential experienced by
Q2 due to Q1 increases. Gravity should be
ignored. Then, you must be:
Moving Q1 closer to Q2
Moving Q1 further away from Q2
Moving in the same direction as the field due to Q1
Moving in the opposite direction to that of the field due to
Q1
Any of the above
2) You move two point charges such that the potential...

A point charge q1=4.20 nC is fixed at the origin. A second point
charge q2=−7.80 nC is fixed at the point x=15.0 cm.
(a) Find the point on the +x axis where the electric potential
is zero.
(b) A third charge, q3=−2.30 nC is then placed at the point
x=20.0 cm. Find the net force acting on charge q2 due to the other
two charges.

Four point charges are given as: +2q, +2q, −2q and –2q. Place
these charges on an x-y coordinate system, with two of them are on
the x and y axis, so that the electric field at point (3 cm, 3cm)
would be zero. Find
i) Electric field at the origin if the above point charges
magnitude is 5.0 μC.
ii) Potential energy of the above configuration.

(1)(A)When removing a wool sweater, a static discharge of 8.83
µC dissipates 7.52 10-3 J of energy. What voltage was
involved?
(B)Two protons are released from rest, one from location 1 and
another from location 2. When these two protons reach location 3,
the first proton has a speed that is 4 times the speed of the
second proton. If the electric potentials at locations 1 and 2 are
231 V and 115 V, respectively, what is the electric potential...

Two small beads having positive charges q1 = 28q and q2 = q are
fixed at the opposite ends of a horizontal insulating rod of length
d = 1.50 m. The bead with charge q1 is at the origin. As shown in
the figure below, a third small, charged bead is free to slide on
the rod.

Problem 4: Two point charges,
Q1 and
Q2, are located on the
x axis as follows. Q1
is at the origin and has a value of +24 µC. The charge
Q2 is at x = 4 meters
and its magnitude and sign are unknown. It is known that the net
electric field due to these two charges is zero at the coordinate x
= 8 meters. (k = 1/4πεo
= 9 x 109 Nt x
m2/C2)
a. Find the magnitude...

Part A) Two particles with positive charges q1 and
q2 are separated by a distance s.
Along the line connecting the two charges, at what distance from
the charge q1 is the total electric field from the two charges
zero?
Express your answer in terms of some or all of the
variables s,
q1,
q2 and
k =14πϵ0. If
your answer is difficult to enter, consider simplifying it, as it
can be made relatively simple with some work.
Part B)...

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